Y=3x^2+48

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Solution for Y=3x^2+48 equation: 



=3Y^2+48

We move all terms to the left:

-(3Y^2+48)=0

We get rid of parentheses

-3Y^2-48=0

a = -3; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·(-3)·(-48)
Δ = -576
Delta is less than zero, so there is no solution for the equation

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